If you are a fan of Harry Potter, you would know the world of magic has its own currency system – as Hagrid explained it to Harry, “Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it’s easy enough.” Your job is to write a program to compute A+B where A and B are given in the standard form of “Galleon.Sickle.Knut” (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28

``````#include "stdio.h"
const int Galleon = 17 * 29;
const int Sickle = 29;
int main(){
int a1, a2, a3;
int b1, b2, b3;
scanf("%d.%d.%d %d.%d.%d", &a1, &a2, &a3, &b1, &b2, &b3);
long long a, b, c;
a = a1 * Galleon + a2 * Sickle + a3;
b = b1 * Galleon + b2 * Sickle + b3;
c = a + b;
printf("%lld.%lld.%lld", c / Galleon, c % Galleon / Sickle, c % Sickle);
return 0;
}
``````

``````#include "stdio.h"
const int Galleon = 17;
const int Sickle = 29;
int main(){
int a1, a2, a3;
int b1, b2, b3;
scanf("%d.%d.%d %d.%d.%d", &a1, &a2, &a3, &b1, &b2, &b3);
//处理Knuts进位
a3 += b3;
a2 += a3 / Sickle;
a3 %= Sickle;
//处理Sickle进位
a2 += b2;
a1 += a2 / Galleon;
a2 %= Galleon;
//处理Galleon
a1 += b1;

printf("%d.%d.%d", a1, a2, a3);
return 0;
}
``````